Home›MPPSC Forest›State Forest Service Mains Exam›Section 'B': Forestry and General Science›UNIT-07: Physics›Refraction of light: Laws of refraction, refraction by glass slab, critical angle, total internal reflection and daily life applications, lenses (converging and diverging), focal length, optical centre, image formation by lens, human eye (defects and remedies), comparison between photographic camera and human eye, simple telescope and astronomical telescope›The power of convex lens of focal length 25 cm is

The power of convex lens of focal length 25 cm is

20192M#mppsc-forest#pyq#mcq#2019
A.1D
B.2D
C.3D
D.4DCorrect
Explanation & Solution

Correct Answer: (D) 4D

Power of a lens is given by the formula P=1/fP = 1/fP=1/f, where fff is in meters. For a convex lens with focal length f=25 cm=0.25 mf = 25 cm\text{ cm} cm = 0.25 m\text{ m} mf=25 cm=0.25 m, the power is P=1/0.25=+4 DP = 1/0.25 = +4 D\text{ D} DP=1/0.25=+4 D.

हिंदी में प्रश्न एवं आदर्श उत्तर

किसी 25 cm फोकस दूरी वाले उत्तल लेंस की शक्ति क्या होगी ?

A.1D
B.2D
C.3D
D.4Dसही

सही उत्तर: (D) 4D

लेंस की क्षमता का सूत्र P=1/fP = 1/fP=1/f होता है, जहाँ fff मीटर में है। 25 cm (0.250.250.25 मीटर) फोकस दूरी वाले उत्तल लेंस की शक्ति P=1/0.25=+4 DP = 1/0.25 = +4 D\text{ D} DP=1/0.25=+4 D होगी।

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