Home›MPPSC Forest›State Forest Service Mains Exam›Section 'B': Forestry and General Science›UNIT-07: Physics›Electricity and its effects: Electric intensity, potential, potential difference, electric current, Ohm's law, resistance, specific resistance, factors influencing resistance, combination of resistance (numerical examples), thermal effect of current and its use, calculation of power and electrical energy spent (numerical), precautions in electric experiments›A piece of wire of resistance R is cut into five equal parts. These

A piece of wire of resistance R is cut into five equal parts. These parts are then connected in parallel. If equivalent resistance is R' then the ratio of R/R' is

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A.1/25
B.1/5
C.5
D.25Correct
Explanation & Solution

Correct Answer: (D) 25

A wire of resistance R is divided into 5 equal parts, each having resistance R/5. When connected in parallel, the equivalent resistance R' is given by 1/R' = 5/(R/5) + ... = 25/R, which yields R/R' = 25.

हिंदी में प्रश्न एवं आदर्श उत्तर

यदि एक तार जिसका प्रतिरोध R है, को पांच बराबर भागों में बाँट दिया जाता है तथा इन्हें समानांतर क्रम में जोड़ दिया जाता है । यदि तुल्य प्रतिरोध R' हो, तो R/R' का अनुपात होगा

A.1/25
B.1/5
C.5
D.25सही

सही उत्तर: (D) 25

R प्रतिरोध के तार को पांच बराबर भागों में बांटने पर प्रत्येक का प्रतिरोध R/5 होगा। इन्हें समानांतर क्रम में जोड़ने पर तुल्य प्रतिरोध R' = R/25 प्राप्त होता है, जिससे अनुपात R/R' का मान 25 आता है।

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