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Home›MPPSC Forest›State Forest Service Mains Exam›Section 'B': Forestry and General Science›UNIT-10: Elementary Mathematics and General Mental Ability›Simple formula and their use factors, H.C.F., L.C.M. by factors, fractions, simple equations›If f₁ = 6x²y and f₂ = 15 xy², then which of the following option is

If f₁ = 6x²y and f₂ = 15 xy², then which of the following option is true ?

20203M#mppsc-forest#pyq#mcq#2020
A.H.C.F. (f₁, f₂) = 45xy, L.C.M. (f₁, f₂) = 30x²y²
B.H.C.F. (f₁, f₂) = 30xy, L.C.M. (f₁, f₂) = 30x³y³
C.H.C.F. (f₁, f₂) = 3xy, L.C.M. (f₁, f₂) = 90x²y²
D.H.C.F. (f₁, f₂) = 3xy, L.C.M. (f₁, f₂) = 30x²y²Correct
Explanation & Solution

The correct answer is (D) H.C.F. (f₁, f₂) = 3xy, L.C.M. (f₁, f₂) = 30x²y².

  • Factorization: f1=6x2y=2⋅3⋅x2⋅yf_1 = 6x^2y = 2 ⋅\cdot⋅ 3 ⋅\cdot⋅ x^2 ⋅\cdot⋅ yf1​=6x2y=2⋅3⋅x2⋅y and f2=15xy2=3⋅5⋅x⋅y2f_2 = 15xy^2 = 3 ⋅\cdot⋅ 5 ⋅\cdot⋅ x ⋅\cdot⋅ y^2f2​=15xy2=3⋅5⋅x⋅y2.
  • HCF & LCM: HCF=gcd⁡(6,15)⋅x⋅y=3xyHCF\text{HCF}HCF = \gcd(6, 15) ⋅\cdot⋅ x ⋅\cdot⋅ y = 3xyHCF=gcd(6,15)⋅x⋅y=3xy. LCM=lcm(6,15)⋅x2⋅y2=30x2y2LCM\text{LCM}LCM = lcm\text{lcm}lcm(6, 15) ⋅\cdot⋅ x^2 ⋅\cdot⋅ y^2 = 30x^2y^2LCM=lcm(6,15)⋅x2⋅y2=30x2y2.

हिंदी में प्रश्न एवं आदर्श उत्तर

यदि f₁ = 6x²y और f₂ = 15 xy² हो, तो निम्नलिखित में से कौन-सा पर्याय सही है ?

A.महत्तम समापवर्तक (f₁, f₂) = 45xy, लघुतम समापवर्त्य (f₁, f₂) = 30x²y²
B.महत्तम समापवर्तक (f₁, f₂) = 30xy, लघुतम समापवर्त्य (f₁, f₂) = 30x³y³
C.महत्तम समापवर्तक (f₁, f₂) = 3xy, लघुतम समापवर्त्य (f₁, f₂) = 90x²y²
D.महत्तम समापवर्तक (f₁, f₂) = 3xy, लघुतम समापवर्त्य (f₁, f₂) = 30x²y²सही

सही उत्तर (D) H.C.F. (f₁, f₂) = 3xy, L.C.M. (f₁, f₂) = 30x²y² है।

  • गुणनखंड: f1=6x2y=2⋅3⋅x2⋅yf_1 = 6x^2y = 2 ⋅\cdot⋅ 3 ⋅\cdot⋅ x^2 ⋅\cdot⋅ yf1​=6x2y=2⋅3⋅x2⋅y और f2=15xy2=3⋅5⋅x⋅y2f_2 = 15xy^2 = 3 ⋅\cdot⋅ 5 ⋅\cdot⋅ x ⋅\cdot⋅ y^2f2​=15xy2=3⋅5⋅x⋅y2।
  • महत्तम व लघुत्तम समापवर्त्य: HCF=3xyHCF\text{HCF}HCF = 3xyHCF=3xy और LCM=30x2y2LCM\text{LCM}LCM = 30x^2y^2LCM=30x2y2।
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