Home›MPPSC Forest›State Forest Service Mains Exam›Section 'B': Forestry and General Science›UNIT-07: Physics›Nuclear energy: Nuclear fission, fusion, chain reaction, nuclear reactor, uses and harms of nuclear energy, general information about M.P. Energy Development Corporation (MPUVN)›For a successful operation of a thermonuclear reactor, Lawson's

For a successful operation of a thermonuclear reactor, Lawson's criterion is given by

20213M#mppsc-forest#pyq#mcq#2021
A.nτn\taunτ T <= 50∗102050 * 10^2050∗1020 keVs/m3keVs/m^3keVs/m3
B.nτn\taunτ T <= 150∗1020150 * 10^20150∗1020 keVs/m3keVs/m^3keVs/m3
C.nτn\taunτ T >= 50∗102050 * 10^2050∗1020 keVs/m3keVs/m^3keVs/m3
D.nτn\taunτ T >= 150∗1020150 * 10^20150∗1020 keVs/m3keVs/m^3keVs/m3Correct
Explanation & Solution

Correct Answer: (D) nτ\tauτ T >= 150 * 10^20 keVs/m^3

Lawson's criterion specifies the minimum confinement product of plasma density (n), energy confinement time (tau), and temperature (T) required for net energy-producing thermonuclear fusion, which is approximately n*tau*T >= 150 * 10^20 keVs/m^3 for D-T fusion.

हिंदी में प्रश्न एवं आदर्श उत्तर

थर्मोन्यूक्लियर रिएक्टर के सफल संचालन के लिए लॉसन का मानदंड है

A.nτn\taunτ T <= 50∗102050 * 10^2050∗1020 keVs/m3keVs/m^3keVs/m3
B.nτn\taunτ T <= 150∗1020150 * 10^20150∗1020 keVs/m3keVs/m^3keVs/m3
C.nτn\taunτ T >= 50∗102050 * 10^2050∗1020 keVs/m3keVs/m^3keVs/m3
D.nτn\taunτ T >= 150∗1020150 * 10^20150∗1020 keVs/m3keVs/m^3keVs/m3सही

सही उत्तर: (D) nτ\tauτ T >= 150 * 10^20 keVs/m^3

थर्मोन्यूक्लियर रिएक्टर के सफल संचालन के लिए लॉसन का मानदंड यह निर्धारित करता है कि प्लाज्मा घनत्व (n), ऊर्जा संरोध समय (tau) और तापमान (T) का गुणनफल n*tau*T >= 150 * 10^20 keVs/m^3 होना चाहिए।

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