Home›MPPSC Forest›State Forest Service Mains Exam›Section 'B': Forestry and General Science›UNIT-07: Physics›Light: Nature of light, reflection of light, laws of reflection, reflection from plane and curved surface, image formation by plane, convex and concave mirror, relation between focal length and radius of curvature, determination of focal length of concave mirror by single pin method, relation between u, v, f (numerical examples)›A convex mirror has a radius of curvature of 22 cm. An object is

A convex mirror has a radius of curvature of 22 cm. An object is placed 14 cm away from the mirror. The lateral magnification of the image will be

20213M#mppsc-forest#pyq#mcq#2021
A.+0.44Correct
B.-0.44
C.+0.84
D.-0.24
Explanation & Solution

Correct Answer: (A) +0.44

For a convex mirror, the radius of curvature R = 22 cm gives a focal length f = R / 2 = 11 cm. Using the mirror formula 1/f = 1/v + 1/u with u = -14 cm, we find v = +6.16 cm, leading to lateral magnification m = -v/u = +0.44.

हिंदी में प्रश्न एवं आदर्श उत्तर

एक उत्तल दर्पण की वक्रता त्रिज्या 22 cm है। एक वस्तु दर्पण से 14 cm दूरी पर रखी गई है। छवि का पार्श्व आवर्धन होगा

A.+0·44सही
B.-0·44
C.+0·84
D.-0·24

सही उत्तर: (A) +0·44

उत्तल दर्पण की वक्रता त्रिज्या 22 cm होने पर फोकस दूरी f = +11 cm होगी। वस्तु की दूरी u = -14 cm रखने पर दर्पण सूत्र से आवर्धन निकालने पर पार्श्व आवर्धन का मान +0.44 प्राप्त होता है।

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