Home›MPPSC Mains (Eng)›General Studies III›Part B: Science, Technology & Public Health›Unit 2: Computer Science›Mathematical Science: Numbers and its type, Methods of Unit Measurement, Equations and Factors, Profit loss, Percentage, Simple and Compound Interest, Ratio-Proportion›The population of a town is 176400. There is increase in it at the

The population of a town is 176400. There is increase in it at the rate of 5% annually. What will be the population of the town after two years?

20156M
Model Answer

Population Growth Math Solution: Pnew=P(1+r100)n=176400(1+5100)2=176400(2120)2=176400×441400=194,481P_{new} = P(1 + r100\frac{r}{100}100r​)^n = 176400 (1 + 5100\frac{5}{100}1005​)^2 = 176400 (2120\frac{21}{20}2021​)^2 = 176400 ×\times× 441400\frac{441}{400}400441​ = 194,481\mathbf{194,481}194,481Pnew​=P(1+100r​)n=176400(1+1005​)2=176400(2021​)2=176400×400441​=194,481.

हिंदी में प्रश्न एवं आदर्श उत्तर

एक कस्बे की जनसंख्या 176400 है। इसमें 5% वार्षिक दर से वृद्धि होती है। 2 वर्ष बाद कस्बे की जनसंख्या कितनी होगी ?

जनसंख्या वृद्धि गणना: P=176400(1+5100)2=176400×441400=194,481P = 176400 (1 + 5100\frac{5}{100}1005​)^2 = 176400 ×\times× 441400\frac{441}{400}400441​ = 194,481\mathbf{194,481}194,481P=176400(1+1005​)2=176400×400441​=194,481। 2 वर्ष बाद जनसंख्या 1,94,481 होगी।

See this question in context →
Free Android App

Practice Better on the StatePYQ Mobile App

⚡ Error Diary · ⏱ Timed Mains Answer Pacer · 📴 Offline Revision Vault

Get it onGoogle Play