Home›MPPSC Mains (Eng)›General Studies III›Part B: Science, Technology & Public Health›Unit 2: Computer Science›Mathematical Science: Numbers and its type, Methods of Unit Measurement, Equations and Factors, Profit loss, Percentage, Simple and Compound Interest, Ratio-Proportion›The population of a city increases by 10% annually. If its present

The population of a city increases by 10% annually. If its present population is 20000, find the population of the city after 2 (two) years.

20225M
Model Answer

Mathematical Demographic Solution:

  1. Present Baseline Population (P) = 20,000
  2. Annual Growth Rate (R) = 10%
  3. Time Period (n) = 2 years
  4. Compounded Population Growth Formula:
    A = P × [1 + (R / 100)]ⁿ
    A = 20,000 × (1 + 0.1)² = 20,000 × (1.1)² = 20,000 × 1.21 = 24,200

Final Answer: The population of the city after 2 years will be 24,200.

हिंदी में प्रश्न एवं आदर्श उत्तर

एक शहर की जनसंख्या में 10% की वार्षिक दर से वृद्धि होती है। यदि इसकी वर्तमान जनसंख्या 20000 है, तो 2 वर्ष पश्चात शहर की जनसंख्या ज्ञात कीजिए।

हल:

  1. वर्तमान जनसंख्या P = 20,000
  2. वार्षिक वृद्धि दर R = 10%
  3. समय n = 2 वर्ष
  4. 2 वर्ष पश्चात जनसंख्या का सूत्र:
    A = P × [1 + (R / 100)]ⁿ
    A = 20,000 × [1 + (10 / 100)]²
    A = 20,000 × (1.1)² = 20,000 × 1.21 = 24,200

उत्तर: 2 वर्ष पश्चात शहर की जनसंख्या 24,200 होगी।

See this question in context →
Free Android App

Practice Better on the StatePYQ Mobile App

⚡ Error Diary · ⏱ Timed Mains Answer Pacer · 📴 Offline Revision Vault

Get it onGoogle Play