Skip to content / सामग्री पर जाएँ
Home›MPPSC Prelims›Paper 2: General Aptitude Test (CSAT)›General Aptitude›Basic Numeracy and Data Interpretation›Basic Numeracy: Numbers and their Relations, Order of Magnitude (Class X level)›If 9 men completed 1/3rd of a work in 8 days working 8 hrs per day,

If 9 men completed 1/3rd of a work in 8 days working 8 hrs per day, how many more men should be engaged to finish the rest of the work in 4 days working one extra hour a day?

20202Mprelimsyear-2020p2
A.(A) 23Correct
B.(B) 32
C.(C) 36
D.(D) 46
Explanation & Solution

Correct Answer: (A) 23

Using the work formula M1D1H1W1=M2D2H2W2M1D1H1W1\frac{M_1 D_1 H_1}{W_1}W1​M1​D1​H1​​ = M2D2H2W2\frac{M_2 D_2 H_2}{W_2}W2​M2​D2​H2​​W1​M1​D1​H1​​=W2​M2​D2​H2​​, we have 9×8×81/3=M2×4×92/39×8×81/3\frac{9 \times 8 \times 8}{1/3}1/39×8×8​ = M2×4×92/3\frac{M_2 \times 4 \times 9}{2/3}2/3M2​×4×9​1/39×8×8​=2/3M2​×4×9​, which simplifies to M2=32M_2 = 32M2​=32 total men required. Since 9 men are already working, the number of additional men needed is 32−9=2332 - 9 = 2332−9=23.

हिंदी में प्रश्न एवं आदर्श उत्तर

यदि 9 पुरुष 8 घंटे प्रतिदिन काम करके 8 दिनों में 1/3 काम को पूरा कर पाते हैं, तो कितने अतिरिक्त लोग बाकी काम को प्रतिदिन एक अतिरिक्त घंटा काम करके 4 दिनों में पूरा कर पाएंगे?

A.(A) 23सही
B.(B) 32
C.(C) 36
D.(D) 46

सही उत्तर: (A) 23

कार्य सूत्र M1D1H1W1=M2D2H2W2M1D1H1W1\frac{M_1 D_1 H_1}{W_1}W1​M1​D1​H1​​ = M2D2H2W2\frac{M_2 D_2 H_2}{W_2}W2​M2​D2​H2​​W1​M1​D1​H1​​=W2​M2​D2​H2​​ के अनुसार: 9×8×81/3=M2×4×92/39×8×81/3\frac{9 \times 8 \times 8}{1/3}1/39×8×8​ = M2×4×92/3\frac{M_2 \times 4 \times 9}{2/3}2/3M2​×4×9​1/39×8×8​=2/3M2​×4×9​। इसे हल करने पर कुल आवश्यक पुरुष M2=32M_2 = 32M2​=32 मिलते हैं। चूँकि 9 पुरुष पहले से कार्यरत हैं, अतः अतिरिक्त आवश्यक पुरुषों की संख्या 32−9=2332 - 9 = 2332−9=23 होगी।

See this question in context →
WhatsApp