Home›MPPSC Prelims›Paper 2: General Aptitude Test (CSAT)›General Aptitude›Basic Numeracy and Data Interpretation›Basic Numeracy: Numbers and their Relations, Order of Magnitude (Class X level)›The median of the following data is: 17, 8, 9, 5, 26, 19, 13, 26, 29

The median of the following data is:
17, 8, 9, 5, 26, 19, 13, 26, 29

20242Mprelimsyear-2024p2
A.(A) 13
B.(B) 17Correct
C.(C) 18
D.(D) 19
Explanation & Solution

The correct answer is (B) 17.

Step-by-step median computation:

  • Given dataset (n=9n = 9n=9 observations): 17,8,9,5,26,19,13,26,2917, 8, 9, 5, 26, 19, 13, 26, 2917,8,9,5,26,19,13,26,29.
  • Arrange the data in ascending numerical order:
  • 5,8,9,13,<strong>17</strong>,19,26,26,295, 8, 9, 13, <strong>17</strong>, 19, 26, 26, 295,8,9,13,<strong>17</strong>,19,26,26,29.
  • For odd n=9n = 9n=9, the median is the (n+12)th=(9+12)th=5th\left(n+12\frac{n + 1}{2}2n+1​\right)th\text{th}th = \left(9+12\frac{9 + 1}{2}29+1​\right)th\text{th}th = 5th\text{th}th(2n+1​)th=(29+1​)th=5th term.
  • The 5th value in the ordered list is 17.

हिंदी में प्रश्न एवं आदर्श उत्तर

निम्नलिखित आंकड़ों की माध्यिका है:
17, 8, 9, 5, 26, 19, 13, 26, 29

A.(A) 13
B.(B) 17सही
C.(C) 18
D.(D) 19

सही उत्तर (B) 17 है।

माध्यिका की चरणबद्ध गणना:

  • दिए गए आंकड़े (n=9n = 9n=9 पद): 17,8,9,5,26,19,13,26,2917, 8, 9, 5, 26, 19, 13, 26, 2917,8,9,5,26,19,13,26,29।
  • आंकड़ों को आरोही (बढ़ते) क्रम में व्यवस्थित करने पर:
  • 5,8,9,13,<strong>17</strong>,19,26,26,295, 8, 9, 13, <strong>17</strong>, 19, 26, 26, 295,8,9,13,<strong>17</strong>,19,26,26,29।
  • विषम संख्या n=9n = 9n=9 के लिए माध्यिका = (n+12)\left(n+12\frac{n + 1}{2}2n+1​\right)(2n+1​)वाँ पद = 5वाँ पद।
  • आरोही क्रम में 5वाँ पद 17 है।
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