30 g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar was mixed in 280 ml of water in vessel B and 20 g of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is :

Question

Accepted Answer

Correct Option: (d) less sweet than that in C To compare the sweetness of the sugar solution in the vessels, we determine the concentration of sugar (grams of sugar per milliliter of water) in each vessel. For Vessel A: Concentration = 30 g ÷ 180 ml = 1/6 g/ml ≈ 0.167 g/ml. For Vessel B: Concentration = 40 g ÷ 280 ml = 1/7 g/ml ≈ 0.143 g/ml. For Vessel C: Concentration = 20 g ÷ 100 ml = 1/5 g/ml = 0.200 g/ml. Comparing the values, we find that 0.200 (Vessel C) > 0.167 (Vessel A) > 0.143 (Vessel B). Therefore, the sweetness of the solution in vessel B is the lowest among all three vessels. Comparing vessel B with vessel C, vessel B is clearly less sweet than vessel C (since 0.143 < 0.200). Thus, option (d) is the correct statement.

30 g of sugar was mixed in 180 ml water in a vessel A, 40 g of sugar was mixed in 280 ml of water in vessel B and 20 g of sugar was mixed in 100 ml of water in vessel C. The solution in vessel B is :

हिंदी में प्रश्न एवं आदर्श उत्तर