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An 8-digit number 4252746B leaves remainder 0 when divided by 3. How many values of B are possible?

20193Mprelimsupscyear-2019p2quantitative-aptitudequantitative-abilitynumbers
A.2
B.3
C.4Correct
D.6
Explanation & Solution

The correct answer is (C) 4.

Explanation:

We are given an 8-digit number 4252746B which leaves remainder 0 when divided by 3 (meaning it is divisible by 3). According to the divisibility rule for 3, the sum of all the digits of the number must be divisible by 3. Let's sum the digits: 4 + 2 + 5 + 2 + 7 + 4 + 6 + B = 30 + B. For 30 + B to be divisible by 3, since 30 is already a multiple of 3, B must be a multiple of 3. Since B represents a single digit from 0 to 9, the possible values for B are 0, 3, 6, and 9. Counting these values, there are 4 possible values for B. Let's check options: 2, 3, 4, 6. Option 4 corresponds to index 2.

हिंदी में प्रश्न एवं आदर्श उत्तर

आठ अंकों की एक संख्या 4252746B को 3 से भाग देने पर शेषफल 0 रहता है । B के कितने मान संभव हैं?

A.2
B.3
C.4सही
D.6

सही उत्तर (C) 4 है।

व्याख्या:

We are given an 8-digit number 4252746B which leaves remainder 0 when divided by 3 (meaning it is divisible by 3). According to the divisibility rule for 3, the sum of all the digits of the number must be divisible by 3. Let's sum the digits: 4 + 2 + 5 + 2 + 7 + 4 + 6 + B = 30 + B. For 30 + B to be divisible by 3, since 30 is already a multiple of 3, B must be a multiple of 3. Since B represents a single digit from 0 to 9, the possible values for B are 0, 3, 6, and 9. Counting these values, there are 4 possible values for B. Let's check options: 2, 3, 4, 6. Option 4 corresponds to index 2.

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