Home›UPSC Prelims›Paper 2: General Studies II (CSAT)›Civil Services Aptitude Test (CSAT)›Basic Numeracy & Data Interpretation›How many triplets (x, y, z) satisfy the equation x + y + z = 6, where

How many triplets (x, y, z) satisfy the equation x + y + z = 6, where x, y and z are natural numbers?

20193Mprelimsupscyear-2019p2quantitative-aptitudequantitative-abilitylinear-equation
A.4
B.5
C.9
D.10Correct
Explanation & Solution

The correct answer is (D) 10.

Explanation:

Since x, y, z are natural numbers and their sum is 6, we need to list all possible combinations. By systematic listing, we get 10 different combinations: (1,1,4), (1,4,1), (4,1,1), (1,2,3), (1,3,2), (2,1,3), (2,2,2), (2,3,1), (3,1,2), (3,2,1).

हिंदी में प्रश्न एवं आदर्श उत्तर

समीकरण x + y + z = 6 को कितने त्रिक (x, y, z) संतुष्ट करते हैं, जहाँ x, y और z धनपूर्णांक संख्याएँ हैं?

A.4
B.5
C.9
D.10सही

सही उत्तर (D) 10 है।

व्याख्या:

Since x, y, z are natural numbers and their sum is 6, we need to list all possible combinations. By systematic listing, we get 10 different combinations: (1,1,4), (1,4,1), (4,1,1), (1,2,3), (1,3,2), (2,1,3), (2,2,2), (2,3,1), (3,1,2), (3,2,1).

See this question in context →
Free Android App

Practice Better on the StatePYQ Mobile App

⚡ Error Diary · ⏱ Timed Mains Answer Pacer · 📴 Offline Revision Vault

Get it onGoogle Play