Home›UPSC Prelims›Paper 2: General Studies II (CSAT)›Civil Services Aptitude Test (CSAT)›Logical Reasoning and Analytical Ability›If LSJXVC is the code for MUMBAI, the code for DELHI is

If LSJXVC is the code for MUMBAI, the code for DELHI is

20183Mprelimsupscyear-2018p2logical-reasoningcoding-decoding
A.CCIDDCorrect
B.CDKGH
C.CCJFG
D.CCIFE
Explanation & Solution

Correct Option: CCIDD

To decode the pattern, let us analyze the relationship between the word 'MUMBAI' and its coded form 'LSJXVC' by looking at the position of each letter in the alphabetical order (where A = 1, B = 2, ..., Z = 26): - M (13) - 1 = L (12) - U (21) - 2 = S (19) - M (13) - 3 = J (10) - B (2) - 4 = X (24) (wrapping around: 2 - 4 = -2, and 26 - 2 = 24) - A (1) - 5 = V (22) (wrapping around: 1 - 5 = -4, and 26 - 4 = 22) - I (9) - 6 = C (3) The pattern is to subtract 1, 2, 3, 4, 5, and 6 respectively from the letter positions. Applying this same rule to 'DELHI': - D (4) - 1 = C (3) - E (5) - 2 = C (3) - L (12) - 3 = I (9) - H (8) - 4 = D (4) - I (9) - 5 = D (4) The code for 'DELHI' is therefore 'CCIDD'. Therefore, Option A is the correct answer.

हिंदी में प्रश्न एवं आदर्श उत्तर

यदि MUMBAI के लिए कूट है LSJXVC, तो DELHI के लिए कूट है

A.CCIDDसही
B.CDKGH
C.CCJFG
D.CCIFE

सही उत्तर: CCIDD

कूट के पैटर्न को समझने के लिए, हम शब्द 'MUMBAI' और उसके कूट 'LSJXVC' के बीच प्रत्येक अक्षर के वर्णमाला क्रम (A = 1, B = 2, ..., Z = 26) के स्थान के संबंध का विश्लेषण करते हैं: - M (13) - 1 = L (12) - U (21) - 2 = S (19) - M (13) - 3 = J (10) - B (2) - 4 = X (24) (चक्रानुसार: 2 - 4 = -2, अर्थात 26 - 2 = 24) - A (1) - 5 = V (22) (चक्रानुसार: 1 - 5 = -4, अर्थात 26 - 4 = 22) - I (9) - 6 = C (3) यहाँ पैटर्न क्रमशः 1, 2, 3, 4, 5, और 6 घटाने का है। इसी नियम को 'DELHI' पर लागू करने पर: - D (4) - 1 = C (3) - E (5) - 2 = C (3) - L (12) - 3 = I (9) - H (8) - 4 = D (4) - I (9) - 5 = D (4) अतः 'DELHI' का कूट 'CCIDD' होगा। इसलिए, विकल्प A सही उत्तर है।

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