A person walks 100 m straight from his house, turns left and walks 100 m, again turns left and walks 300 m, then turns right and walks 100 m to reach his office. In which direction does he walk initially from his house if his office is exactly in the North-East direction?

Correct Option: (c) South

Let us trace the path of the person assuming his initial direction from his house is South. 1. Walks 100 m South: position becomes (0, -100). 2. Turns left: facing East. Walks 100 m: position becomes (100, -100). 3. Turns left again: facing North. Walks 300 m: position becomes (100, -100 + 300) = (100, 200). 4. Turns right: facing East. Walks 100 m: final position becomes (100 + 100, 200) = (200, 200). Since the final position (200, 200) is in the first quadrant where both x (East) and y (North) are positive and equal, the office is exactly in the North-East direction from his house. This matches the given condition perfectly. If he had started in any other direction like North-West, West, or South-West, the final position would not lie in the exact North-East. Thus, his initial direction must be South. Hence, the correct option is (c).