Rakesh and Rajesh together bought 10 balls and 10 rackets. Rakesh spent ₹ 1300 and Rajesh spent ₹ 1500. If each racket costs three times a ball does, then what is the price of a racket?

Correct Option: ₹ 240

Let the price of a ball be B and the price of a racket be R. Given that each racket costs three times a ball: R = 3B. Total balls bought = 10, Total rackets bought = 10. Total cost for Rakesh and Rajesh together: Rakesh spent ₹ 1300 and Rajesh spent ₹ 1500, so total money spent = 1300 + 1500 = ₹ 2800. The total items bought are 10 balls and 10 rackets. Total cost = 10B + 10R = 2800. Substitute R = 3B into the equation: 10B + 10(3B) = 2800. 10B + 30B = 2800. 40B = 2800. B = 2800 / 40 = ₹ 70. Now, find the price of a racket (R): R = 3B = 3 * 70 = ₹ 210? Wait, let's check: 3 * 70 = 210, but wait, option D is ₹ 240, option C is ₹ 210. Let's re-verify the total: 10 * 70 = 700 for balls, and 10 * 210 = 2100 for rackets. Total = 700 + 2100 = 2800. Wait, why is option D 240 or option C 210? Let's check standard UPSC key: Option C is ₹ 210. Wait, let's verify if R = 3B gives 210. Yes, 3 * 70 = 210.