For a sports meet, a winners' stand comprising three wooden blocks is in the following form: Large, Medium, Small blocks. There are six different colours available to choose from and each of the three wooden blocks is to be painted such that no two of them has the same colour. In how many different ways can the winners' stand be painted?

Correct Option: 120

The winners' stand consists of three distinct wooden blocks: Large (L), Medium (M), and Small (S). We have 6 different colours available to paint these blocks, and no two blocks can have the same colour. This is a standard permutation problem where we need to assign 3 distinct colours out of 6 to 3 distinct positions (L, M, S). - For the Large block, we can choose any of the 6 available colours (6 options). - For the Medium block, we can choose any of the remaining 5 colours (5 options). - For the Small block, we can choose any of the remaining 4 colours (4 options). Using the fundamental principle of counting, the total number of different ways to paint the stand is: 6 × 5 × 4 = 120 ways. Thus, option A is the correct answer. The other options are incorrect as they do not correctly apply the rule of distinct selection without replacement.