There are four statements X, Y, Z and W. Their relations are as follows :
If X is incorrect, then so is Z; if Y is incorrect, then W is correct; if W is correct, then X is incorrect.

Which of the following is/are correct?
I. If X is correct, then so is Y.
II. If Z is correct, then it is not necessary that Y is correct.

Select the answer using the code given below.

Correct Answer: (A) I only

The given logical rules are: (1) $\neg X$$\implies$ \neg Z, (2) $\neg Y$$\implies$ W, and (3) $W$$\implies$ \neg X. Chaining rules (2) and (3) yields $\neg Y$$\implies$ \neg X. The contrapositive of this implication is $X$$\implies$ Y, which proves Statement I ('If X is correct, then so is Y') is valid. For Statement II, the contrapositive of rule (1) is $Z$$\implies$ X. Combining this with $X$$\implies$ Y gives $Z$$\implies$ Y, meaning that if Z is correct, Y must necessarily be correct. This contradicts the assertion in Statement II that Y is not necessarily correct. Thus, only Statement I is correct.