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Home›UPSC Prelims›Paper 2: General Studies II (CSAT)›Civil Services Aptitude Test (CSAT)›Basic Numeracy & Data Interpretation›What is the value of 'X' in the sequence 2, 7, 22, 67, 202, X, 1822?

What is the value of 'X' in the sequence 2, 7, 22, 67, 202, X, 1822?

20213Mprelimsupscyear-2021p2quantitative-aptitude
A.(a) 603
B.(b) 605
C.(c) 607Correct
D.(d) 608
Explanation & Solution

Correct Answer: (C) 607

The sequence follows the recurrence relation Tn=3Tn−1+1T_n = 3 T_{n-1} + 1Tn​=3Tn−1​+1: 2×3+1=72 ×\times× 3 + 1 = 72×3+1=7, 7×3+1=227 ×\times× 3 + 1 = 227×3+1=22, 22×3+1=6722 ×\times× 3 + 1 = 6722×3+1=67, 67×3+1=20267 ×\times× 3 + 1 = 20267×3+1=202. Applying this rule to find XXX: X=202×3+1=606+1=607X = 202 ×\times× 3 + 1 = 606 + 1 = 607X=202×3+1=606+1=607. Continuing the pattern confirms 607×3+1=1822607 ×\times× 3 + 1 = 1822607×3+1=1822.

हिंदी में प्रश्न एवं आदर्श उत्तर

अनुक्रम 2, 7, 22, 67, 202, X, 1822 में 'X' का मान क्या है ?

A.(a) 603
B.(b) 605
C.(c) 607सही
D.(d) 608

सही उत्तर: (C) 607

यह श्रृंखला संबंध Tn=3Tn−1+1T_n = 3 T_{n-1} + 1Tn​=3Tn−1​+1 का पालन करती है: 2×3+1=72 ×\times× 3 + 1 = 72×3+1=7, 7×3+1=227 ×\times× 3 + 1 = 227×3+1=22, 22×3+1=6722 ×\times× 3 + 1 = 6722×3+1=67, 67×3+1=20267 ×\times× 3 + 1 = 20267×3+1=202। अतः XXX का मान 202×3+1=606+1=607202 ×\times× 3 + 1 = 606 + 1 = 607202×3+1=606+1=607 होगा। आगे 607×3+1=1822607 ×\times× 3 + 1 = 1822607×3+1=1822 इस नियम की पुष्टि करता है।

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