मुख्य›संघ लोक सेवा आयोग प्रारंभिक परीक्षा›प्रश्न पत्र 2: सामान्य अध्ययन II (CSAT)›सिविल सेवा अभिरुचि परीक्षण (CSAT)›आधारभूत संख्यान एवं आंकड़ों का निर्वचन›आठ अंकों की एक संख्या 4252746B को 3 से भाग देने पर शेषफल 0 रहता है ।

आठ अंकों की एक संख्या 4252746B को 3 से भाग देने पर शेषफल 0 रहता है । B के कितने मान संभव हैं?

20193Mprelimsupscyear-2019p2quantitative-aptitudequantitative-abilitynumbers
A.2
B.3
C.4सही
D.6
व्याख्या एवं हल

सही उत्तर (C) 4 है।

व्याख्या:

We are given an 8-digit number 4252746B which leaves remainder 0 when divided by 3 (meaning it is divisible by 3). According to the divisibility rule for 3, the sum of all the digits of the number must be divisible by 3. Let's sum the digits: 4 + 2 + 5 + 2 + 7 + 4 + 6 + B = 30 + B. For 30 + B to be divisible by 3, since 30 is already a multiple of 3, B must be a multiple of 3. Since B represents a single digit from 0 to 9, the possible values for B are 0, 3, 6, and 9. Counting these values, there are 4 possible values for B. Let's check options: 2, 3, 4, 6. Option 4 corresponds to index 2.

In English (Question & Model Answer)

An 8-digit number 4252746B leaves remainder 0 when divided by 3. How many values of B are possible?

A.2
B.3
C.4Correct
D.6

The correct answer is (C) 4.

Explanation:

We are given an 8-digit number 4252746B which leaves remainder 0 when divided by 3 (meaning it is divisible by 3). According to the divisibility rule for 3, the sum of all the digits of the number must be divisible by 3. Let's sum the digits: 4 + 2 + 5 + 2 + 7 + 4 + 6 + B = 30 + B. For 30 + B to be divisible by 3, since 30 is already a multiple of 3, B must be a multiple of 3. Since B represents a single digit from 0 to 9, the possible values for B are 0, 3, 6, and 9. Counting these values, there are 4 possible values for B. Let's check options: 2, 3, 4, 6. Option 4 corresponds to index 2.

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