Correct Answer: (B) 111
Rewriting the equation: 10m×103×n=10m+3n=7525×2532×3275. Prime factorizing the right-hand side: 7525=(3×52)25=325×55075^{25} = (3 ×\times× 5^2)^{25} = 3^{25} ×\times× 5^{50}7525=(3×52)25=325×550, 2532=(52)32=56425^{32} = (5^2)^{32} = 5^{64}2532=(52)32=564, and 3275=(25)75=237532^{75} = (2^5)^{75} = 2^{375}3275=(25)75=2375. Thus, RHS=2375×325×5114RHS\text{RHS}RHS = 2^{375} ×\times× 3^{25} ×\times× 5^{114}RHS=2375×325×5114. Because nnn is not divisible by 10, the factor 10m+310^{m+3}10m+3 must contain all common pairs of prime factors 2 and 5. The maximum power of 10 dividing the RHS is min(375,114)=114\min(375, 114) = 114min(375,114)=114. Therefore, m+3=114 ⟹ m=111m + 3 = 114 ⟹ \implies⟹ m = 111m+3=114⟹m=111.