मुख्य›संघ लोक सेवा आयोग प्रारंभिक परीक्षा›प्रश्न पत्र 2: सामान्य अध्ययन II (CSAT)›सिविल सेवा अभिरुचि परीक्षण (CSAT)›तार्किक तर्क और विश्लेषणात्मक क्षमता›Location of B is north of A and location of C is east of A. The

Location of B is north of A and location of C is east of A. The distances AB and AC are 5 km and 12 km respectively. The shortest distance (in km) between the locations B and C is

20142Mprelimsupscyear-2014p2csatlogical-reasoningdirections
A.60
B.13सही
C.17
D.7
व्याख्या एवं हल

सही उत्तर: (B) 13

The position considered forms a right-angle triangle leading to the conclusion derived from Pythagorean theorem.

In English (Question & Model Answer)

Location of B is north of A and location of C is east of A. The distances AB and AC are 5 km and 12 km respectively. The shortest distance (in km) between the locations B and C is

A.60
B.13Correct
C.17
D.7

Correct Option: (B) 13

The position considered forms a right-angle triangle leading to the conclusion derived from Pythagorean theorem.

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