अनुक्रम 132, 129, 124, 117, 106, 93, X में X क्या है?

20193Mprelimsupscyear-2019p2quantitative-aptitude
A.74
B.75
C.76सही
D.77
व्याख्या एवं हल

सही उत्तर: (C) 76

श्रेणी के क्रमागत पदों का अंतर बढ़ती हुई अभाज्य संख्याएँ हैं: 132−129=3132 - 129 = 3, 129−124=5129 - 124 = 5, 124−117=7124 - 117 = 7, 117−106=11117 - 106 = 11, तथा 106−93=13106 - 93 = 13। अगली अभाज्य संख्या 17 है, अतः X=93−17=76X = 93 - 17 = 76 होगा।

In English (Question & Model Answer)

What is X in the sequence 132, 129, 124, 117, 106, 93, X ?

A.74
B.75
C.76Correct
D.77

Correct Answer: (C) 76

The differences between consecutive terms in the sequence are consecutive prime numbers in increasing order: 132−129=3132 - 129 = 3, 129−124=5129 - 124 = 5, 124−117=7124 - 117 = 7, 117−106=11117 - 106 = 11, and 106−93=13106 - 93 = 13. The next prime number is 17, so X=93−17=76X = 93 - 17 = 76.

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